How to derive equation number three from a graph.
Equation 3 is d = V1Δt + ½aΔt².
The area of the (A) rectangle is d = V1Δt.
The area of the (B) triangle is d = ½ (V2 - V1) (Δt).
Therefore, the displacement is equal to the area of the area of the (A) rectangle plus the (B) triangle.
From the big five's equation 1, V2 - V1 = aΔt
Sub equation 1 into the displacement equation.
d = V1Δt + ½ (aΔt) (Δt)
d = V1Δt + ½aΔt
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